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N eq = m g / m eq = 45 / 47,60 = 0,94 eq Calcoliamo infine la normalità (N) dal rapporto tra il numero di equivalenti del sale e il volume in litri della soluzione N = n eq / V soluzione = 0,94 / 2,3 = 0,41 (eq/L) La normalità della soluzione è pertanto 0,41 eq/L Ti potrebbe interessare anche da equivalenti a moliLarghezza 10 cm / 100 = 0,1 m;Notazione scientifica 1,03e03 Notazione ingegneria 0,103e4 Conversione Densità gratuita e online Convertire 1,03 g/cm3 in kg/m3 (grammi/centimetro cubo in chilogrammi/metro cubo) Quanto fa 1,03 g/cm3 in kg/m3? Chem 152 Exam 2 Flashcards Quizlet ƒCƒPƒƒ" •½ˆÀ ‹M'° ƒCƒ‰ƒXƒg

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